class= "wxlogin-btn loginButton" open- type= "getPhoneNumber" bindgetphonenumber= "getPhoneNumber" >微信用户快捷登陆 
wx66e0aab98b4d306a的appid，获取手机号提示："该appid没有权限"？The appid of wx66e0aab98b4d306a, get the mobile phone number prompt: "This appid does not have permission"?
wx66e0aab98b4d306a的appid，获取手机号提示："该appid没有权限"？ class= "wxlogin-btn loginButton" open- type= "getPhoneNumber" bindgetphonenumber= "getPhoneNumber" >微信用户快捷登陆 Class = "wxlogin BTN loginButton" open type = "getphonenumber" bindetphonenumber = "getphonenumber" > wechat users can log in quickly
回答：
主体认证过了嘛？
群主管理都是支付大佬
进行小程序微信认证了吗？