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一维数组循环按条件合并给二维数组的问题，逻辑实在想不通了，请教各位大神？

//数组1
var sensorList:[
      {"id":10000,"category": "sensor","name": "温度","value": "1"},
      {"id":10001,"category": "sensor","name": "湿度","value": "2"},
      {"id":10002,"category": "sensor","name": "气压","value": "3"},
      {"id":10003,"category": "sensor","name": "光照","value": "4"},
      {"id":10004,"category": "sensor","name": "风速","value": "5"},
      {"id":10005,"category": "sensor","name": "雨量","value": "6"},
      {"id":10006,"category": "sensor","name": "PM2.5","value": "20"},
      {"id":10007,"category": "sensor","name": "PM10","value": "21"},
      {"id":10008,"category": "sensor","name": "风向","value": "37"},
      {"id":10009,"category": "sensor","name": "风向","value": "38"},
      {"id":10000,"category": "sensorUnit","name": "℃","value": "1"},
      {"id":10101,"category": "sensorUnit","name": "%","value": "2"},
      {"id":10102,"category": "sensorUnit","name": "kPa","value": "3"},
      {"id":10103,"category": "sensorUnit","name": "kLux","value": "4"},
      {"id":10104,"category": "sensorUnit","name": "m/s","value": "5"},
      {"id":10105,"category": "sensorUnit","name": "mm/h","value": "6"},
      {"id":10106,"category": "sensorUnit","name": "ug/m3","value": "20"},
      {"id":10107,"category": "sensorUnit","name": "ug/m3","value": "21"},
      {"id":10108,"category": "sensorUnit","name": "°","value": "37"},
      {"id":10109,"category": "sensorUnit","name": "","value": "38"},
      {"id":10002,"category": "windDir","name": "北","value": "16"},
      {"id":10003,"category": "windDir","name": "北偏东","value": "1"},
      {"id":10004,"category": "windDir","name": "东北","value": "2"},
      {"id":10005,"category": "windDir","name": "东偏北","value": "3"},
      {"id":10006,"category": "windDir","name": "东","value": "4"},
      {"id":10007,"category": "windDir","name": "东偏南","value": "5"},
      {"id":10008,"category": "windDir","name": "东南","value": "6"},
      {"id":10009,"category": "windDir","name": "南偏东","value": "7"},
      {"id":10000,"category": "windDir","name": "南","value": "8"},
      {"id":10101,"category": "windDir","name": "南偏西","value": "9"},
      {"id":10102,"category": "windDir","name": "西南","value": "10"},
      {"id":10103,"category": "windDir","name": "西偏南","value": "11"},
      {"id":10104,"category": "windDir","name": "西","value": "12"},
      {"id":10105,"category": "windDir","name": "西偏北","value": "13"},
      {"id":10106,"category": "windDir","name": "西北","value": "14"},
      {"id":10107,"category": "windDir","name": "北偏西","value": "15"},
      {"id":10108,"category": "windDir","name": "静风","value": "17"},
      {"id":10109,"category": "windDir","name": "静风","value": "18"}
    ],
//数组2
   var monitorList:[
      {
        id: 10001382,
        name: "测试01",
        listsensor:[
        {monitorid:10001382,sensorid:1,value: 11.1},
        {monitorid:10001382,sensorid:2,value: 22.2},
        {monitorid:10001382,sensorid:37,value: 180},
        {monitorid:10001382,sensorid:38,value: 2}
        ]},
      {
        id: 10001383,
        name: "测试02",
        listsensor:[
        {monitorid:10001383,sensorid:3,value: 11.1},
        {monitorid:10001383,sensorid:4,value: 22.2},
        {monitorid:10001383,sensorid:37,value: 180},
        {monitorid:10001383,sensorid:38,value: 2}
        ]}
  ]
//需求结果
/* newList:[
      {id: 10001382,name: "测试01",listsensor:[
        {monitorid:10001382,sensorid:1,value: 11.1,name:"温度"，unit:"℃"},
        {monitorid:10001382,sensorid:2,value: 22.2,name:"湿度"，unit:"%"},
        {monitorid:10001382,sensorid:37,value: 180,name:"风向"，unit:"°"},
        {monitorid:10001382,sensorid:38,value: 4,name:"风向"，unit:"东"}
      ]},
      {id: 10001383,name: "测试02",listsensor:[
        {monitorid:10001383,sensorid:3,value: 11.1,name:"气压"，unit:"kPA"},
        {monitorid:10001383,sensorid:4,value: 22.2,name:"光照"，unit:"kLux"},
        {monitorid:10001383,sensorid:37,value: 180,name:"风向"，unit:"°"},
        {monitorid:10001383,sensorid:38,value: 2,name:"风向"，unit:"东北"}
      ]}
] */
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3 个回答

  • HardPan
    HardPan
    2022-04-11

    我的方法：

    先定义一维数组需要的数据：

    var var newArr = [];
let newListsensor = [];
var arr1 = this.data.sensorList.filter(item=>{return item.category==="sensor"})
var arr2 = this.data.sensorList.filter(item=>{return item.category==="sensorUnit"})
for(let i=0;i<arr1.length;i++){
            let obj = arr1[i],num=obj.value,flag=false;
            for(let j=0;j<arr2.length;j++){
                let aj = arr2[j],n=aj.value,yearObj={};
                if(n==num){
                    flag=true;
                    yearObj["sensorid"]=num||n;
                    yearObj["name"] = obj.name;
                    yearObj["unit"] = aj.name;
                    newArr.push(yearObj);
                }
            }
}
  //得到新数组
  /*newArr:[
  {sensorid: "1", name: "温度", unit: "℃"},
  {sensorid: "2", name: "湿度", unit: "%"},
  {sensorid: "3", name: "气压", unit: "kPa"},
  {sensorid: "4", name: "光照", unit: "kLux"},
  {sensorid: "5", name: "风速", unit: "m/s"},
  {sensorid: "6", name: "雨量", unit: "mm/h"},
  {sensorid: "20", name: "PM2.5", unit: "ug/m3"},
  {sensorid: "21", name: "PM10", unit: "ug/m3"},
  {sensorid: "37", name: "风向", unit: "°"},
  {sensorid: "38", name: "风向", unit: ""}
  ]
for(let i=0;i<monitorList.length;i++){
  newListsensor.push(monitorList[i].listsensor)
}

    /*newListsensor:[

    ]

    push成一个二维数组之后怎么跟newArr,通过“sensorid”进行数据合并呢？


    2022-04-11
    有用
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  • 武曲心
    武曲心
    2022-04-11

    如果要做数据提交的话就做循环来组装数据，如果只是用来渲染页面的话用通过sensorid用wxs匹配查找sensorList来实现

    2022-04-11
    有用
    回复 9
    • HardPan
      HardPan
      发表于移动端
      2022-04-11
      是用来做数据渲染的，最后取结果的时候是把整个取到的数组内容渲染出来了。
      2022-04-11
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    • 武曲心
      武曲心
      2022-04-11回复HardPan
      2022-04-11
      赞
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    • HardPan
      HardPan
      2022-04-11
      您好！这个数据没有渲染出来呢？是哪个判断有问题吗？
      2022-04-11
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    • 武曲心
      武曲心
      2022-04-11回复HardPan
      我只是给你思路，wxs数据判断部分自己改
      2022-04-11
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    • HardPan
      HardPan
      2022-04-11
      好的非常感谢，我先试着改一下。
      2022-04-11
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    查看更多(4)
  • 嘿ོ，我ོ就ོ是那个小伙🍊ོ
    嘿ོ，我ོ就ོ是那个小伙🍊ོ
    2022-04-11

    你这两个数据结构就不合理，关联性极差，就算合成估计也会有数据错乱

    2022-04-11
    有用
    回复 1
    • HardPan
      HardPan
      发表于移动端
      2022-04-11
      我的想法是先把一维数组里面的结构合并一下，在给二维数组循环按照条件合并。但是结果不太理想。需要循环太多次了
      2022-04-11
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